In the diagram, QTR is a straight line and < PQT = 30^\circ. Find the sin of < PTR
Attached Figure / Diagram
A
\(\frac{8}{15}\)
B
\(\frac{2}{3}\)
C
\(\frac{3}{4}\)
D
\(\frac{15}{16}\)
Verified Correct Answer: C.
Step-by-Step Mathematical Solution
\(\frac{10}{\sin 30^o} = \frac{15}{\sin x} = \frac{10}{0.5} = \frac{15}{\sin x}\)
\(\frac{15}{20} = \sin x\)
sin x = \(\frac{15}{20} = \frac{3}{4}\)
N.B x = < PTR
Source: Myschool Past Questions Archive (Record #33080)