TQ is tangent to circle XYTR, < YXT = 32o, RTQ = 40o. find < YTR
Attached Figure / Diagram
A
108o
B
121o
C
140o
D
148o
Verified Correct Answer: A.
Step-by-Step Mathematical Solution
< TXR = < QTR = 40o (alternate segment)
< TWR = < TXR = 40o(Angles in the same segments)
< YXR = 40o + 32o = 72o
< YXR + < YTR = 180o(Supplementary)
72o + < YTR = 180o
< YTR = 180o - 72o
= 108o
Source: Myschool Past Questions Archive (Record #33079)