A chord of a circle radius \(\sqrt{3cm}\) subtends an angle of 60^\circ on the circumference of he circle. Find the length of the chord
A
\(\frac{\sqrt{3}}{2}\)
B
\(\frac{3}{2}\)
C
3
D
\(\sqrt{3}\)cm
Verified Correct Answer: D.
Step-by-Step Mathematical Solution
Length of chord = \(2r \times \sin(\frac{\theta}{2})\)
= \( 2 \times \sqrt{3} \times \sin(\frac{60}{2})\)
= \(2 \times \sqrt{3} \times \frac{1}{2}\)
= \(\sqrt{3}\) cm.
Source: Myschool Past Questions Archive (Record #33081)