In the diagram above, PQR is a straight line and PS is a tangent to the circle QRS with /PS/ = /SR/ and ∠SPR = 40^\circ. Find ∠PSQ
Attached Figure / Diagram
A
40o
B
30o
C
20o
D
10o
Verified Correct Answer: A.
Step-by-Step Mathematical Solution
R = P (base ∠s of isc \Delta, ps = RS)
∴R = 40^\circ
∠PSQ = R (∠s in alternate segment)
∴∠PSQ = 40^\circ
Source: Myschool Past Questions Archive (Record #11108)