\theta = 45 x 2 (∠ at center twice ∠ at \theta) \theta = 90^\circ Area of sector = \(\frac{\theta}{360}\) x \pir\(^2\) = \(\frac{90}{360}\) x \(\frac{22}{7}\) x 7 x 7 = \(\frac{77}{2}\)cm\(^2\) Area of triangle = \(\frac{1}{2}\) ab sin \theta = \(\frac{1}{2}\) x 7 x 7 sin 90 = \(\frac{1}{2}\) x 7 x 7 x 1 = \(\frac{49}{2}\) cm\(^{2}\) Area of shaded region = \(\frac{77}{2}\) - \(\frac{49}{2}\) = \(\frac{28}{2}\) = 14cm\(^2\)