A triangle has vertices P(-1,6), Q(-3, -4) and R(1, -4).Find the midpoint of PQ and QR respectively.
A
(0,-2) and (-1, -4)
B
(-1,0) and (-1,-1)
C
(-2,1) and (0,1)
D
(-2,1) and (-1,-4)
Verified Correct Answer: D.
Step-by-Step Mathematical Solution
Midpoint of PQ \(\frac{x_2 + x_1}{2};\frac{y_2 + y_1}{2}\)
=\(\frac{-1+(-3)}{2};\frac{6-4}{2}\)
=\(\frac{-4}{2};\frac{2}{2}\)
= -2, 1
Midpoint of QR = \(\frac{x_2 + x_1}{2};\frac{y_2 + y_1}{2}\)
\(\frac{-3+1}{2};\frac{-4-4}{2}\)
\(\frac{-2}{2};\frac{-8}{2}\)
-1, -4
Midpoint of PQ and QR = (-2,1) and (-1,-4)
Source: Myschool Past Questions Archive (Record #11109)