A body whose mass is 2kg and has a volume of 500cm3 just floats when completely immersed in a liquid. Calculate the density of the liquid
A
4.0 x 102kgm-3
B
4.0 x 103kgm-3
C
1.0 x 103kgm-3
D
1.0 x 106kgm-3
Verified Correct Answer: B.
Physical Principles & Numerical Solution
since the object floats, density of liquid = density of object
converting 500cm3 to m3,
\(\frac{500}{10^{6}} = 5 \times 10^{-4}m^{3}\)
D = \(\frac{m}{v}\)
= \(\frac{2}{5 \times 10^{-4}}\)
=\(4.0 \times 10^{3}kgm^{-3}\)
Source: Myschool Past Questions Archive (Record #28373)