A force, 10N, drags a mass 10kg on a horizontal table with an acceleration of 0.2ms. If the acceleration due to gravity is 10ms-1, the coefficient of friction between the moving mass and the table is
A
0.02
B
0.08
C
0.20
D
0.80
Verified Correct Answer: B.
Physical Principles & Numerical Solution
\(\mu\)mg = ma
\(\mu\)mg = F - ma
\(\mu\) x 10 x 10 = 10 - (10 x 0.2)
100 \(\mu\) =10 - 2
dividing both sides by 100
\(\mu\) = 8 / 100
\(\mu\) = 0.08
Source: Myschool Past Questions Archive (Record #28372)