Y = sin \pi(150\pit - \(\frac{\pix}{4}\)) Comparing the above with the standard wave equation: Y = A sin \pi (\(\frac{(2vt)}{\lambda}\) - \(\frac{(2x)}{\lambda}\)) => the phase difference \(\frac{x}{4}\) = \(\frac{2x}{\lambda}\) ∴ \(\frac{1}{4}\) = \(\frac{2}{\lambda}\) => \lambda = 8cm ∴ \(\frac{2\pix}{8}\) = 45^\circ since \pi = 180^\circ 45^\circ X 8 = 2 X 180^\circ x ∴ x = 1cm