An engine of a car of power 80 kW moves on a rough road with a velocity of 32 m\(s^-1\). The forces required to bring it to rest is
A
2.56 x 106N
B
2.50 x 106N
C
2.80 x 103N
D
2.50 x 103N
Verified Correct Answer: D.
Physical Principles & Numerical Solution
Power = force x velocity
=> 80,000 = F x 32
F = \(\frac{80000}{32}\)
= 2500N
= 2.50 x \(10^3\)N
Source: Myschool Past Questions Archive (Record #14333)