\(\frac{\text{x}}{2}\) - \(\frac{\text{y}}{5}\) = 1 - - - - - - 1 y - \(\frac{\text{x}}{3}\) = 8 - - - - - 2 We clear the fractions by multiplying through by the lcm of 2 and 5 = 10 for eqn 1 and 3 for eqn 2 5x - 2y = 10 - - - - - - - 3 3y - x = 24 - - - - - - - - - 4 from eqn 4, make x the subject of formula x = 3y - 24 (after multiply thru by -1, so x can be positive) Put x = 3y - 24 into eqn 3 5(3y - 24) - 2y = 10 15y - 120 - 2y = 10 15y - 2y = 10 + 120 13y = 130 y = \(\frac{130}{13}\) = 10 y = 10 put in eqn 4 3y - x = 24 - - - - - - - - - 4 3(10) - x = 24 30 - x = 24 - x = 24 - 30 = -6 x = 6 ( minus cancels out minus) Therefore, x = 6, y = 10.