\(\frac{16^{2 + x}}{4} = 64^x\) 16\(^{2 + x} = 4 \times 64^x\) 4\(^{2(2 + x)} = 4^1 \times 4^{3(x)}\) (Equate coefficients since the bases are the same) 2(2 + x) = 1 + 3x 4 + 2x = 1 + 3x 2x - 3x = 1 - 4 -x = -3 x = 3.