If the angle of a sector of a circle with radius 10.5 cm is 120^\circ, find the perimeter of the sector. [Take \(\pi = \frac{22}{7}\)]
A
48 cm
B
40 cm
C
43 cm
D
45 cm
Verified Correct Answer: C.
Step-by-Step Mathematical Solution
Perimeter of the sector = \(2r + \frac{\theta}{360^\circ} \times 2\pi r\)
= \(2(10.5) + \frac{120}{360} \times 2 \times \frac{22}{7} \times 10.5\)
= \(21 + 22\)
= 43 cm
Source: Myschool Past Questions Archive (Record #54929)