Determine the value of \(\int_0 ^{\frac{\pi}{2}
}(-2cos x)dx\)
A
-2
B
-1/2
C
-3
D
-3/2
Verified Correct Answer: A.
Step-by-Step Mathematical Solution
\(\int_0 ^{\frac{\pi}{2}}(-2cos x)dx = [-2sin x + c]_0 ^{\frac{\pi}{2}}\)
=(-2sin\(\frac{\pi}{2}+c+2sin0-c)\)
=-2sin90+c+2sin0-c
=-2(1)+2(0)
=-2
Source: Myschool Past Questions Archive (Record #9224)