f(x) = 2x\(^3\) - x\(^2\) - 4x – 4 f’(x) = 6x\(^2\) - 2x – 4 As f’(x) = 0 Implies 6x\(^2\) - 2x – 4 = 0 3x – x – 2 = 0 (By dividing by 2) (3x + 2)(x - 1) = 0 3x + 2 = 0 implies x = \(\frac{-2}{3}\) Or x - 1 = 0 implies x = 1 f’(x) = 6x\(^2\) - 2x – 4 f’’(x) = 12x – 2 At max point f’’(x) < 0 ∴f’’(x) = 12x – 2 at x = 1 = 12(1) – 2 = 12 – 2 = 10 ∴ Max at x = \(\frac{-2}{3}\)