Make c the subject of the equation a(b + c) + \(\frac{5}{d}\) - 2 = 0
A
c = \(\frac{2d - 5 - b}{ad}\)
B
c = \(\frac{2d - 5 - abd}{ad}\)
C
c = \(\frac{2d - 5 - ab}{ad}\)
D
c = \(\frac{5 - 2d - b}{ad}\)
Verified Correct Answer: B.
Step-by-Step Mathematical Solution
a(b + c) + \(\frac{5}{d}\) - 2 = 0
ab + ac + \(\frac{5}{d}\) - 2 = 0
abd + \(\frac{acd}{d}\) + 5 - 2 = ab + ac + 5 - 2d
acd = 2d - 5 - abd
c = \(\frac{2d - 5 - abd}{ad}\)
Source: Myschool Past Questions Archive (Record #32665)