PQRS is a cyclic quadrilateral with PQ as diameter of the circle. If o find < QRS
A
75o
B
37\(\frac{1}{2}\)o
C
127\(\frac{1}{2}\)o
D
105o
Verified Correct Answer: D.
Step-by-Step Mathematical Solution
PSO = 90o(angle in a semicircle)
SPO = 180o - (90o + 15o) = 75o
o - 75o
= 105o(opposite angles in cyclic quadrilateral are supplementary)
Source: Myschool Past Questions Archive (Record #32664)