In the diagram above, O is the center of the circle, BOC is a diameter and angle ADC is 37o
What is ACB?
Attached Figure / Diagram
A
147o
B
127o
C
65o
D
53o
E
37o
Verified Correct Answer: D.
Step-by-Step Mathematical Solution
From the figure \(< ABC = < ADC = 37^\circ\) (angles on the same segment)
\(< BCA = 90^\circ\) (angle in semi-circle)
\(\therefore\) In \(\Delta ABC\), \(< ACB = 180^\circ - (37^\circ + 90^\circ)\)
= 53^\circ
Source: Myschool Past Questions Archive (Record #22148)