In GP, when you are given three consecutive terms, say f, g, h, then \(f \times h = g^2\) Given: \(x, \frac{3}{2}, \frac{6}{7}, y\), then \(\frac{6x}{7} = (\frac{3}{2})^2 \implies \frac{6x}{7} = \frac{9}{4} ... (i)\) Also, \(\frac{3y}{2} = (\frac{6}{7})^2 \implies \frac{3y}{2} = \frac{36}{49} ... (ii)\) From \(\frac{6x}{7} = \frac{9}{4} \implies x = \frac{9 \times 7}{6 \times 4}\) \(x = \frac{21}{8}\) Also, \(\frac{3y}{2} = \frac{36}{49} \implies y = \frac{2 \times 36}{3 \times 49}\) = \(\frac{24}{49}\) \(xy = \frac{21}{8} \times \frac{24}{49} = \frac{9}{7}\)