Let the first term be \( a \), and the common ratio be \( r \). Given: - Second term: \( ar = 1 \) - Fifth term: \( ar^4 = \frac{1}{8} \) From the first equation, we have: \(a = \frac{1}{r}\) Substituting into the second equation: \(\frac{1}{r} r^4 = \frac{1}{8}\) \(r^3 = \frac{1}{8}\) Taking the cube root gives: \(r = \frac{1}{2}\) Thus, the common ratio is \(\frac{1}{2}\)