In a basket of fruits, there are 6 grapes, 11 bananas, and 13 oranges. If one fruit is chosen at random, what is the probability that the fruit is either a grape or a banana?
A
\(\frac{17}{30}\)
B
\(\frac{11}{30}\)
C
\(\frac{6}{30}\)
D
\(\frac{5}{30}\)
Verified Correct Answer: A.
Step-by-Step Mathematical Solution
Total fruits = 6 + 11 + 13 = 30
Favorable (grape or banana) = 6 + 11 = 17
Probability = \(\frac{17}{30}\)
Source: Myschool Past Questions Archive (Record #74158)