The probability that Amaka will pass an examination is \(\frac{3}{7}\) and that Bala will pass is \(\frac{4}{9}\). Find the probability that both will pass the examination.
A
\(\frac{2}{21}\)
B
\(\frac{4}{21}\).
C
\(\frac{5}{21}\)
D
\(\frac{9}{21}\)
Verified Correct Answer: B.
Step-by-Step Mathematical Solution
Pr(Amaka passes) = \(\frac{3}{7}\), Pr(Bala passes) = \(\frac{4}{9}\).
Pr(both Amaka and Bala pass the exam) = \(\frac{3}{7}\) x \(\frac{4}{9}\) = \(\frac{4}{21}\).
Source: Myschool Past Questions Archive (Record #71882)