In the diagram \(\overline{TU}\) is a tangent to the circle SPQR at P. If \(\angle\)PTS = 44º, \(\angle\)SQP = 35º, find \(\angle\)PST
Attached Figure / Diagram
A
101º
B
125º
C
130º
D
135º
Verified Correct Answer: A.
Step-by-Step Mathematical Solution
\(\angle\)SPT = 35º (alternate segment)
From \(\triangle\)TSP
44 + \(\angle\)SPT + \(\angle\)PST = 180º (sum of angles in a triangle)
\(\angle\)PST = 180 - 44 - 35 = 101º
Source: Myschool Past Questions Archive (Record #71879)