A 2 μF capacitor is connected directly across a 150 V\(_{rms}\), 60 Hz A.C source. Calculate the r m s value of the current.
A
0.113 A
B
0.160 A
C
150 A
D
1324 A
Verified Correct Answer: A.
Physical Principles & Numerical Solution
X\(_c\) = \(\frac{1}{2\pi FC}\)
X\(_c\) = \(\frac{1}{2 \times 3.142 \times 60 \times 2 \times 10^{-6}}\)
X\(_c\) = 1326.1192\(\Omega\)
I = \(\frac{\text{V}}{X_c}\)
I = \(\frac{150}{1326.1192}\) = 0.113A
Source: WAEC / JAMB / NECO Classroom Archive (Record #72056)