A constant voltage source supplies a sinusoidal alternating e.m.f. The voltage marked against the components are their peak values. Determine the peak value of the applied e.m.f
Attached Figure / Diagram
A
1V
B
4V
C
5V
D
2V
Verified Correct Answer: C.
Physical Principles & Numerical Solution
Effective voltage in an RLC circuit is given by V = \(\sqrt{V_R^2 + (V_L - V_C)^2}\)
V = \(\sqrt{3^2 + (6 - 2)^2}\) = \(\sqrt{3^2 + 4^2}\) = \(\sqrt{9 + 16}\)
= 5V
Source: WAEC / JAMB / NECO Classroom Archive (Record #72054)