What is the amount of heat required to raise the temperature of a 0.02 kg of ice cube from \(-10^oC\) to \(10^oC\) ?
[specific latent heat of fusion of ice = 3.34 x \(10^5\) \(Jkg^-1\), Specific heat capacity of water = 4200 \(Jkg^-1\) \(k^-1\)
Specific heat capacity of ice = 2100 \(Jkg^-1\) \(k^-1\)
A
6680 J
B
1680 J
C
7520 J
D
7940 J
Verified Correct Answer: D.
Physical Principles & Numerical Solution
Quantity of heat required to raise the temperature of the ice cube from \(-10^oC\) to \(0^oC\)
⇒H=mc►ø = 0.02 \times 2100 \times 0 -(-10)
⇒ H = 0.02 \times 2100 \times (0 + 10) = 0.02 \times 2100 \times 10
⇒ H = 420 J
quantity of heat required to melt ice at \(0^oC\)
⇒ H = mL = 0.02 \times 3.34 \times \(10^5\)
⇒H=6680 j
Quantity of heat required to raise the temperature of the melted ice cube (water) from \(0^oC\) to \(-10^oC\)
⇒H=mc►ø = 0.02 \times 4200 \times (10-0)
⇒H = 0.02 \times 4200 \times 10
⇒H = 840j
;420 + 6680 + 840 = 7940 j
Source: WAEC / JAMB / NECO Classroom Archive (Record #67877)