What quantity of heat is required to convert 20 g of ice at 0 ºC to water at the same temperature? (Specific latent heat of ice = 336 Jg\(^{-1}\))
A
7.06 x 10\(^{3}\)J
B
5.38 x 10\(^{3}\)J
C
6.72 x 10\(^{3}\)J
D
1.35 x 10\(^{3}\)J
Verified Correct Answer: C.
Physical Principles & Numerical Solution
quantity of heat = mass * Specific latent heat → 20 * 336
quantity of heat = 6720j or 6.72 x 10\(^{3}\)J
Source: WAEC / JAMB / NECO Classroom Archive (Record #65087)