A gas at a volume of V\(_{0}\) in a container at pressure p\(_{0}\) is compressed to one-fifth of its volume. What will be its pressure if the magnitude of its original temperature T is constant?
A
\(\frac{p_{0}} {5}\)
B
\(\frac{4p_{0}}{5}\)
C
\(p_0\)
D
5\(P_0\)
Verified Correct Answer: D.
Physical Principles & Numerical Solution
\(p_1\) = \(P_0\), \(V_1\) = \(V_0\), \(V_2\) = \(\frac{1}{5}\)\(V_0\) \(P_2\) = ?
\(P_1\)\(V_1\) = \(P_2\)\(V_2\)
\(P_2\) = \(\frac{P_{1}V_{1}}{V_{1}}\)
= \(\frac{\not P_{o}V_{o}}{\frac{1}{5}P_{o}}\) = 5\(\not P_{o}\)
Source: WAEC / JAMB / NECO Classroom Archive (Record #60776)