A given mass of gas has a pressure of 80 Nm\(^{-2}\) at a temperature of 47 C. If the temperature is reduced to 27 C with volume remaining constant, the new pressure is?
A
46.0 Nm\(^{-2}\)
B
75.0 Nm\(^{-2}\)
C
80.0 Nm\(^{-2}\)
D
85.3 Nm\(^{-2}\)
Verified Correct Answer: B.
Physical Principles & Numerical Solution
Using \(\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}\)
\(P_1\) = 80Nm\(^{2}\)
\(T_1\) = 47 + 273 = 320k
\(T_2\) = 27 + 273 = 300k
\(P_2\)?
\(\therefore\) = \(P_2\) = \(\frac{P_{1}T_{2}}{T_{1}}\)
= \(\frac{80 \times 300}{320}\) = 75.Nm\(^{2}\)
Source: WAEC / JAMB / NECO Classroom Archive (Record #60611)