If a load of mass 10N stretched a cord by 1.2cm, what is the total work done?
A
6.0 x 10-2J
B
7.6 x 10-2J
C
1.8 x 10-2J
D
6.6 x 10-2J
Verified Correct Answer: A.
Physical Principles & Numerical Solution
Work done on a stretched cord
= Average force x extension
= \(\frac{1 \times 10 \times 0.012}{2}\)
= 6.0 x 10\(^{-2}\)J
Source: WAEC / JAMB / NECO Classroom Archive (Record #14151)