A spring of force constant 500 Nm\(^{-1}\) is compressed such that its length shortens by 5cm. The energy stored in the spring is?
A
0.625 J
B
6.250 J
C
62.500 J
D
625.000 J
Verified Correct Answer: A.
Physical Principles & Numerical Solution
Energy stored in a spring = (1)/2 K e2 = (1)/2 x 500(0.05)2 = 0.625J
Source: WAEC / JAMB / NECO Classroom Archive (Record #14028)