A body is projected at an angle of 30° to the horizontal with a velocity of 150 ms\(^{-1.}\). Calculate the time it takes to reach the greatest height [Take g = 10 ms\(^2\) and neglect air resistance]
Verified Correct Answer: .
Physical Principles & Numerical Solution
Given Data: u = 150 ms\(^{-1.}\), Ø = 30^\circ
Time of Flight = \(\frac{2usinØ}{g}\) → \(\frac{2 * 150 * sin30^\circ}{10}\)
= 15s
t = time taken to reach maximum height = ?
t = usin\theta \divg
t = [150 \times sin(30)] \div10
t = 7.5secs.
Source: WAEC / JAMB / NECO Classroom Archive (Record #52980)