A missile is projected so as to attain its maximum range. Calculate the maximum height attained if the initial velocity of projection is 200 ms\(^{-1}\). [g = 10ms\(^{-2}\)]
Verified Correct Answer: .
Physical Principles & Numerical Solution
H = \(\frac{U^2sin^2 \theta}{2g}\)
H = \(\frac{200^2(sin 45^o)^2}{20}\)
= 999.8m or 1000m
Source: WAEC / JAMB / NECO Classroom Archive (Record #52867)