A machine has an efficiency of 80%. If the input work is 200J, the output work is?
A
250J
B
160J
C
120J
D
100J
Verified Correct Answer: B.
Physical Principles & Numerical Solution
\(\text{Efficiency} = \frac{\text{Output Work}}{\text{Input Work}}\)
Given: \(\text{Efficiency} = 80\% = 0.8\), \(\text{Input Work} = 200 \text{ J}\)
Then, the output work is calculated as follows:
\(\text{Output Work} = 0.8 \times 200 = 160 \, \text{J}\)
Thus, the output work is: \(\text{Output Work} = 160 \, \text{J}\).
Source: Myschool Past Questions Archive (Record #74380)