What magnitude of electric current can store 2.5 J of energy in a 3 H induction coil?
A
1.29 A
B
2.48 A
C
5.00 A
D
3.66 A
Verified Correct Answer: A.
Physical Principles & Numerical Solution
Answer: A
Energy in an inductor: E = \(\frac{1}{2}\)LI\(^2\) ⇒ I ≈ 1.29 A.
Source: Myschool Past Questions Archive (Record #74379)