The e.m.f of the accumulator = 1.5v Table of value/observations R(\(\Omega\)) 1\(_{amp}\) 1\(^{-1}_{amp}\) 0 0.78 1.28 1 0.50 2.00 2 0.38 2.63 3 0.30 3.33 4 0.25 4.00 5 0.22 4.55 Slope (s) = \(\frac{y_{2}-y_{1}}{x_{2}-x_{1}} = \frac{4-1}{4-2} = \frac{3}{2}\) The intercept on the vertical axis is =-1.85\(\Omega\) Precautions: I tightened connections. I avoided errors due to parallax in reading ammeter or voltmeter. I noted zero error of ammeter/ voltmeter. I removed key when readings were not taken. I took repeated readings from the table, i.e. averaging the reading. (b)i. - The lead-acid accumulator can be recharged while the Leclanche cell cannot. - The lead-acid accumulator has the capacity to supply large currents for a long time while the leclanche cell does not. ii. The two resistors 3\(\Omega\) and 4\(\Omega\) are connected in parallel. \(\therefore\) The equivalent resistance (\(\Omega\) = \(\frac{1}{R} = \frac{1}{3} = \frac{1}{4} = \frac{4+3}{12}\) = \(\frac{7}{12}\) = 1.71 The effective resistance in the circuit = 1.71 + 4 = 5.71\(\Omega\)