A plane is inclined at an angle \(\theta\) to the horizontal. Its velocity ratio is
A
\(sin\theta\)
B
\(tan\theta\)
C
\(\frac{1}{sin\theta}\)
D
\(\frac{1}{tan\theta}\)
Verified Correct Answer: C.
Physical Principles & Numerical Solution
Velocity ratio = \(\frac{Effort distance}{Load distance}\)
On an inclined plane, it is the inverse of \(sin\theta\) = \(\frac{1}{sin\theta}\)
Source: Myschool Past Questions Archive (Record #49973)