Ice of mass 50g at 0^\circC was completely melted by 70% of the total heat energy supplied. Calculate the total heat energy supplied [Specific latent heat of fusion of ice = 336\(Jg^{-1}\)]
A
2400J
B
6800J
C
7251J
D
24000J
Verified Correct Answer: D.
Physical Principles & Numerical Solution
The quantity of heat needed to melt ice = mL (where m is the mass of ice and L is the specific latent heat of fusion of ice)
Q = \(50 \times 336 = 16800J\) but this is 70% of the total heat supplied so that we have,
70% total heat = 16800J
\(\frac{70}{100}\) of total heat = 16800J
⇒ Total heat supplied = \(\frac{16800\times100}{70} = 24000J\)
Source: Myschool Past Questions Archive (Record #49971)