A cell of internal resistance 2\Omega supplies current to a 6\Omega resistor. The efficiency of the cell is
A
12.0%
B
25.0%
C
33.3%
D
75.0%
Verified Correct Answer: D.
Physical Principles & Numerical Solution
Internal resistance determine the maximum current that can be supplied
Efficiency = \(\frac{R}{R+ r}\) \times 100
= \(\frac{6}{8}\) \times 100
= 75%
Source: Myschool Past Questions Archive (Record #46384)