Calculate the specific latent heat of vaporization of steam of 1.13 x 10\(^6\)J of heat energy is required to convert 15kg of steam to water.
A
7.53 x 105 Jkg\(^{-1}\)
B
7.53 x 10-2Jkg\(^{-1}\)
C
\(7.53 \times 10^{4}\)Jkg\(^{-1}\)
D
7.53 x 10-3Jkg\(^{-1}\)
Verified Correct Answer: C.
Physical Principles & Numerical Solution
Quantity of heat = mass(m) \times specific latent heat (L)
Q = mL
L = \(\frac{Q}{m}\)
= \(\frac{1.13 \times 10^{6}}{15}\)
= \(7.53 \times 10^{4}\)Jkg\(^{-1}\)
Source: Myschool Past Questions Archive (Record #46383)