The line: \(3y + 6x\) = 48 Divide through by 3 ⇒ y + 2\(x\) = 16 ⇒ y = -2\(x\) + 16 ∴ The gradient of the line = -2 The points: A(-2, k) and B (4, 8) m =\(\frac{y2 - y1}{x2 - x1} = \frac{8 - k}{4 - (-2)}\) ⇒ m =\(\frac[8 - k}{4 + 2} = {8 - k}{6}\) Since the line passes through the points ∴ -2 = \(\frac{8 - k}{6}\) ⇒ \(\frac{-2}[1} = \frac{8 - k]{6}\) ⇒ 8 - k = -12 ⇒ k = 8 + 12 ∴ k = 20