\(3x + 2y + 4 = 0\) Rearrange: \(2y = -3x - 4\) Divide both sides by 2 y = \(\frac {-3 \times - 4}{2}\) y = \(\frac {-3}{2} \times - 2\) ∴ the gradient of the line 3x + 2y + 4 = 0 is \(\frac {-3}{2}\) If two lines are perpendicular to each other ∴ \(m_1 x m_2\) = -1 Let \(m_1 = \frac {-3}{2} \therefore m_2 = \frac {-1}{m_1} = \frac {-1}{-3/2} = \frac {2}{3}\) From the equation of a line which is given as m = \(\frac {y - y_1}{x - x_1} where (x_1, y_1) = (2,3)\) \(\therefore \frac {2}{3} = \frac {y - 3}{x - 2}\) =3(y - 3) = 2(x - 2) =3y - 9 = 2 x -4 =3y = 2 x -4 + 9 ∴ 3y = 2x + 5