A solid weights 5.0 N in air, 4.2 N in water and 4.4 N in liquid Y. Calculate the relative density of liquid Y.
A
0.75
B
0.88
C
0.95
D
1.13
E
1.33
Verified Correct Answer: A.
Physical Principles & Numerical Solution
Given: Weight in air = 5.0 N, in water = 4.2 N, in liquid Y = 4.4 N.:
Loss of weight in Water: \( 5.0 - 4.2 = 0.8 \, \text{N} \)
Loss of weight in Liquid Y: \( 5.0 - 4.4 = 0.6 \, \text{N} \)
Relative density of liquid y
\(\text{RD}_{\text{Y}} = \frac{0.6}{0.8} = 0.75\)
The relative density of liquid Y is 0.75
Source: Myschool Past Questions Archive (Record #42722)