In the AC circuit diagram above, the resonance frequency is
Attached Figure / Diagram
A
5000π Hz
B
2500π Hz
C
5000/π Hz
D
2500/π Hz
Verified Correct Answer: D.
Physical Principles & Numerical Solution
resonance frequency \(f_r\) = \(\frac{ 1}{ 2\pi \sqrt{LC}}\)
\(f_r\) = \(\frac{1}{2\pi \sqrt{5\times10^{-6} \times 8\times 10^{-3}}}\)
\(f_r\) = \(\frac{1}{ \pi 0.0004}\)
\(f_r\) = \(\frac{ 2500}{\pi}\)
Source: Myschool Past Questions Archive (Record #41745)