what is the resultant resistance in the circuit given above
Attached Figure / Diagram
A
11Ω
B
8Ω
C
4Ω
D
3.6Ω
E
4.3Ω
Verified Correct Answer: B.
Physical Principles & Numerical Solution
The 2\(\Omega\) resistors are in parallel
R\(_{para}\) = \(\frac{R_1 \times R_2}{R_1 + R_2}\) = \(\frac{2 \times 2}{2 + 2}\) = \(\frac{4}{4}\) = 1 \(\Omega\)
This 1 \(\Omega\) resistor is in series with both the 4 \(\Omega\) and 3 \(\Omega\) resistors
Therefore, R\(_{total}\) = 1 + 4 + 3 = 8 \(\Omega\)
Source: Myschool Past Questions Archive (Record #41624)