what is the resultant capacity of the circuit
Attached Figure / Diagram
A
1.5µF
B
18.0µF
C
6.0µF
D
6.8µF
E
8.83µF
Verified Correct Answer: A.
Physical Principles & Numerical Solution
1\muf and 5\muf are parallel;
Ceff = 1 + 5 = 6\muf
6\muf, 4\muf and 4\muf are in series.
total capacitance of the circuit in series( \(\frac{1}{C_T}\)) = \(\frac{1}{C_1} + \frac{1}{C_2} + \frac{1}{C_3}\)
= \(\frac{1}{4} + \frac{1}{4} + \frac{1}{6}\)
= \(\frac{ 6 + 6 + 4}{ 24}\) = \(\frac{ 16}{ 24}\)
\(\frac{1}{C_T}\) = \(\frac{ 16}{ 24}\)
\(C_T\) = \(\frac{24}{ 16}\) = 1.5\muf.
Source: Myschool Past Questions Archive (Record #41623)