A body of mass 20g projected vertically upwards in vacuum returns to the point of projection after 1.2s. [g = 10ms-2]. Determine the potential energy of the body at the maximum height of its motion
A
0.36J
B
0.72J
C
360.00J
D
720.00J
Verified Correct Answer: A.
Physical Principles & Numerical Solution
P.E at max = K.E on projection
= \(\frac{1}{2}\)mv2 = \(\frac{1}{2} \times 0.02 \times 6^2 = 0.36J\)
Source: Myschool Past Questions Archive (Record #35660)