To find the speed of projection, we can use the formula for the time of flight of an object projected vertically upwards: \(t = \frac{2u}{g}\) where: - \( t \) is the total time of flight (1.2 s), - \( u \) is the initial speed of projection, - \( g \) is the acceleration due to gravity (10 m/s²). Rearranging the formula to solve for \( u \): \(u = \frac{gt}{2}\) Substituting the values: \(u = \frac{10 \, \text{m/s}^2 \times 1.2 \, \text{s}}{2} = \frac{12}{2} = 6 \, \text{m/s}\) Thus, the speed of projection is \( 6 \, \text{m/s} \).