In the diagram above, O is the center of the circle of radius 3.5cm, ∠POQ = 60°. What is the area of the minor sector POQ?
[Take π = 22/7].
Attached Figure / Diagram
A
1481/2cm2
B
77cm2
C
321/12cm2
D
65/12cm2
E
15/6cm2
Verified Correct Answer: D.
Step-by-Step Mathematical Solution
Area of sector = \(\frac{\theta}{360^\circ} \times \pi r^2\)
= \(\frac{60}{360} \times \frac{22}{7} \times 3.5 \times 3.5\)
= \(\frac{77}{12}\)
= \(6\frac{5}{12}\) cm\(^2\)
Source: WAEC / JAMB / NECO Classroom Archive (Record #23809)