The angle of a sector of a circle of diameter 8cm is 135°. Find the area of the sector [Take \(\pi\) = 22/7].
A
\(9\frac{3}{7}cm^2\)
B
\(12\frac{4}{7}cm^2\)
C
\(18\frac{6}{7}cm^2\)
D
\(25\frac{1}{7}cm^2\)
Verified Correct Answer: C.
Step-by-Step Mathematical Solution
Area of a sector
\(\frac{\theta}{360^\circ} * \pir^2\)
= \(\frac{135}{360} * 3.142 * 4 * 4\)
= \(18\frac{6}{7}cm^2\)
Source: WAEC / JAMB / NECO Classroom Archive (Record #22408)